1.

Calculate the binding energy per nucleon of ._20^40Ca. Given that mass of ._20^40Ca nucleus = 20 39.962589 u. mass of a proton = 1.007825 u , mass of neutron = 1.008665 u and luis equivalent to 931 Mev.

Answer»

4.55 Mev
8.55 Mev
6.55 Mev
7.55 Mev

Answer :B


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