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Calculate the binding energy per nucleon of ""_3^7Li (7 u), Given mass of a proton = 1.007825 u and mass of neutron = 1.008665u. |
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Answer» SOLUTION :Mass of 3 proton = `3 XX 1.007825 = 3.023475 U` Mass of 4 neutrons = `4 xx 1.008665 = 4.03466 u` Total mass = 7.058135 u Mass of `""_3^7Li = 7.0878 u` `:.` Mass defect = `0.029665 u` Binding ENERGY = `0.029665 xx 931 MEV = 27.618 MeV` `:.` Binding energy per nucleon = `3.945 MeV`. |
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