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Calculate the capacitance of a capacitor that stores 40microC of charge and has a voltage of 2V.(a) 20F(b) 20microF(c) 10F(d) 10microFThis question was posed to me at a job interview.My question comes from Charge and Voltage in portion Capacitance and Capacitors of Basic Electrical Engineering

Answer»

Right option is (b) 20microF

To elaborate: Q is DIRECTLY PROPORTIONAL to V. The constant of PROPORTIONALITY in this case is C, that is, the capacitance. HENCE C=Q/V.

C=40microC/2V=20microF.



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