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Calculate the change in current in an inductor having inductance 4000H, number of turns is 200 and the flux changes from 760 to 800 Wb.(a) 2A(b) 4A(c) 6A(d) 8AThe question was posed to me in an interview.The question is from Ferromagnetic Cored Inductor in a DC Circuit in division Inductance in a DC Circuit of Basic Electrical Engineering

Answer»

Correct ANSWER is (a) 2A

The best I can explain: From the formula of incremental INDUCTANCE, we KNOW that:

L=(Change in flux/Change in CURRENT)*Number of turns

Substituting the values from the given question, we get a change in current = 2A.



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