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If the flux linkage in coil 1 is 3Wb and it has 500 turns and the current in coil 2 is 2A, calculate the mutual inductance.(a) 750H(b) 500H(c) 450H(d) 900HThis question was posed to me in an online quiz.My doubt is from Mutual Inductance topic in chapter Inductance in a DC Circuit of Basic Electrical Engineering

Answer» RIGHT option is (a) 750H

The best I can explain: We know that mutual inductance is the product of the number of turns in ONE coil and the FLUX linkages of that coil, DIVIDED by the current in the other coil.

M=3*500/2=750H.


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