Calculate the change in entropy for the following reaction `2CO(g) +O_(2)(g) rarr 2CO_(2)(g)` Given: `S_(CO)^(Theta)(g)=197.6 J K^(-1)mol^(-1)` `S_(O_(2))^(Theta)(g)=205.03 J K^(-1)mol^(-1)` `S_(CO_(2))^(Theta)(g)=213.6 J K^(-1)mol^(-1)`

Calculate the change in entropy for the following reaction `2CO(g) +O_

1.	Calculate the change in entropy for the following reaction `2CO(g) +O_(2)(g) rarr 2CO_(2)(g)` Given: `S_(CO)^(Theta)(g)=197.6 J K^(-1)mol^(-1)` `S_(O_(2))^(Theta)(g)=205.03 J K^(-1)mol^(-1)` `S_(CO_(2))^(Theta)(g)=213.6 J K^(-1)mol^(-1)`
Answer» `DeltaS^(Theta) =sum (S^(Theta)) ("products") -sum (S^(Theta)) ("reactants")` `=[2 xx S_(CO_(2))^(Theta)(g) - 2 xx S_(CO)^(Theta)+S_(O_(2))^(Theta)]` `= (213.6 xx2) - (2xx197.6 +205.03)` `= 427.2 - 600.23 =- 173.03 J K^(-1) mol^(-1)`

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Calculate the change in entropy for the following reaction `2CO(g) +O_(2)(g) rarr 2CO_(2)(g)` Given: `S_(CO)^(Theta)(g)=197.6 J K^(-1)mol^(-1)` `S_(O_(2))^(Theta)(g)=205.03 J K^(-1)mol^(-1)` `S_(CO_(2))^(Theta)(g)=213.6 J K^(-1)mol^(-1)`

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