1.

Calculate the change in intensity level when the intensity of sound increases by `10^(6)` times its original intensity.

Answer» Here `= (I)/(I_(0))=("Final intensity")/("Initial intensity")=10^(6)`
Increase in intensity level, `L=10 log_(10)((I)/(I_(0)))=10 log_(10)(10^(6))=10xxlog_(10)10=10xx6xx1=60` decibels.


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