Calculate the change in pressure ( in atm) when 2 mole of `NO` and `16 g O _(2)` in `6.25` litre originally at `27^(@)C` react to produce the maximum quantity of `NO_(2)` possible according to the equation. `( ` Take `R=(1)/(12)` ltr. Atm`//`mol K `)` `2NO(g)+O_(2)(g) hArr 2NO_(2)(g)`A. 1B. 4C. 5D. 2

Calculate the change in pressure ( in atm) when 2 mole of `NO` and `16

1.	Calculate the change in pressure ( in atm) when 2 mole of `NO` and `16 g O _(2)` in `6.25` litre originally at `27^(@)C` react to produce the maximum quantity of `NO_(2)` possible according to the equation. `( ` Take `R=(1)/(12)` ltr. Atm`//`mol K `)` `2NO(g)+O_(2)(g) hArr 2NO_(2)(g)`A. 1B. 4C. 5D. 2
Answer» Correct Answer - 4 `{:(,2NO,+,o_(2)(g),rarr,2NO_(2)(g)),("moles",2,,0.5,,0),(,2-2xx0.5,,0,,2xx0.5),(,1,,0,,1),(,n_(f)=1+1,,,,n_(f)=2+0.5),( :. ,Deltan=(2.5-2),=0.5"moles",,,),( :. ,"change in pressure",,,,):} ` `Deltap=(DeltanRT)/(V)=0.5xx(1)/(12)xx(3300)/(8.25)=2atm`

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