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Calculate the compressibility factor for `SO_(2)` if 1 mole of it occupies 0.35 litre at `300K` and 50 atm pressure Comment on the result . |
Answer» Compressibility factor `(Z) =(PV)/(nRT)` `Z = (40 xx 0.4)/(1 xx 0.0821 xx 300) = 0.65` Since `Z` value is lesser than 1 and thus , `nRT gtPV` In order to have `Z =1` volume of `CO_(2)` must have been more at same `P` and `T` or `Co_(2)` is more compressible than ideal gas . |
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