1.

Calculate the concentration of a solution obtained by mixing `300 g` of `25%` by weight solution of `NH_(4)Cl` and `150 g` of `40%` by weight solution of `NH_(4)Cl`.

Answer» Weight of solution I and II `=300+150=450 g`
Weight of `NH_(4)Cl` in II solution `=(40xx150)/(100)=60 g`
`:.` Total weight of `NH_(4)Cl= 75+60= 135 g`
`:. %` by wt. of mixed solution `=(135)/(450)xx100= 30%`


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