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Calculate the concentration of a solution obtained by mixing `300 g` of `25%` by weight solution of `NH_(4)Cl` and `150 g` of `40%` by weight solution of `NH_(4)Cl`. |
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Answer» Weight of solution I and II `=300+150=450 g` Weight of `NH_(4)Cl` in II solution `=(40xx150)/(100)=60 g` `:.` Total weight of `NH_(4)Cl= 75+60= 135 g` `:. %` by wt. of mixed solution `=(135)/(450)xx100= 30%` |
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