1.

Calculate the current amplification factorbeta ( beta) when change in collector current is 1mA and change in base current is 20 Omega A .

Answer»

Solution :Change in COLLECTOR CURRENT `( Delta I_(C )) = 1m A = 10^(-3) A `
Change in base current `( Delta I_(B))= 20 mu A = 20 xx 10^(-6) A`.
` BETA= ( Delta I_(C ))/(Delta I_(B)) = ( 10^(-3))/( 20 xx 10^(-6))`
`beta = ( 1000)/(20)`
`beta = 50`


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