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Calculate the cut-off wavelength and cutoff frequency of x-rays from an x-ray tube of accelerating potential 20,000 V. |
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Answer» Solution :The cut-off wavelength of the CHARACTERISTIC x-rays is `lambda_(0) = (12400)/(V) Å = (12400)/(20000) Å = 0.62 Å` The corresponding frequency is `V_(0) = (C)/(lambda_(0)) = (3 xx 10^(8))/(0.62 xx 10^(-10))= 4.84 xx 10^(18)` Hz |
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