InterviewSolution
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InterviewSolution
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Calculate the degree of dissociation of HI at `450^(@)C` if the equilibrium constant for the dissociation reaction is `0.263`. |
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Answer» Correct Answer - B `{:(,HI,hArr,1/2H_(2),+,1/2I_(2)),("Initial",1,,0,,0),("At equilibrium",1-x,,x/2,,x/2),(,(1-x)/v,,x/(2v),,x/(2v)):}` `K_(c)=((x/(2v))^(1//2)(x/(2v))^(1//2))/((1-x)/v)` `0.263=(x xx v)/(2vxx(1-x))` `0.263=x/2(1-x~~1)` (x is very small) `x=0.526` |
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