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Calculate the ΔH° of the reaction\(H-\overset{\overset{H}{|}}{\underset{\underset{H}{|}}{C}}-Cl\) (g) → C(g) + 2H(g) + 2Cl(g)(Use table for standard enthalpy of formation). |
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Answer» The given reaction represents a process in which chemical bonds are broken and constituent atoms are produced. Clearly this is a case of atomization of CH2Cl2(g) as in this case no new bond is formed. Thus Bond energy in (to break bonds) 2ΔH°(C-H) = 2 x 413 kJ mol-1 2ΔH°(C-Cl) Bond energy out (to form bond) No bond is formed and ΔH° (out) is zero. = \(\frac{2 \times 328 kJ\,mol^{-1}}{1482\, kJ\,mol^{-1}}\) ΔH°(reaction) = Bond energy in - Bond energy out = 1482 kJ mol-1 - 0 = 1482 kJ mol-1 |
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