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Calculate the dispersive power for crown glass from the given data `mu_(v)=1.523` and `mu_(r)=1.5145`. |
Answer» Here, `mu_(v)=1.523` and `mu_(r)=1.5145` Mean refractive index, `mu=(1.523+1.5145)/(2)=1.51875` Dispersive power is given by, `omega=(mu_(v)-mu_(r))/((mu-1))=(1.523-1.5145)/((1.51875-1))=0.1639` |
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