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Calculate the distance between 5^(th) and 15^(th) bright fringes in an interference pattern obtained by experiment due to narrow slits separated by 0.2mm and illuminated by light of wavelength 560mm. The distance between the slit and screen is 1m. |
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Answer» Solution :`x_(n)=(nlambdaD)/(d)` `x_(5)=(5xx560xx10^(-9)XX1)/(0.2xx10^(-3))=14xx10^(-3)m` `x_(15)=(15xx560xx10^(-19)xx1)/(0.2xx10^(-3))=42xx10^(-3)m` `x_(15)-x_(5)=(42-14)xx10^(-3)=28xx10^(-3)m` |
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