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Calculate the distancefor which ray optics is good aproximation for an aperture of 5 mm and wavelenght 500 nm. |
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Answer» Solution :`a = 5 MM = 5 xx 10^(-3) m ,` `lambda = 500 nm = 500 xx 10^(-9) m, z = ?` Equation for Fresnel.s distance, `z = (a^(2))/(2 lambda)` Substituting, `z=((5xx10^(-3))^(2))/(2xx500xx10^(-9))=(25xx10^(-6))/(1xx10^(-6))=25M` z = 25 m |
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