Calculate the E°cell using these electrodes whose half reactions are: – InterviewSolution

InterviewSolution

1.

Calculate the E°cell using these electrodes whose half reactions are:Fe(OH)2(s) + 2e– → Fe(s) + 2OH–(aq) E° = -0.88V NiO2(s) + 2H2O(l) + 2e– → Ni(OH)2(s) + 2OH–(aq) E° = +0.49V

Answer»

E°cell = (E°_cathode(SRK) - E°_anode(SRP))

(SRP means Standard Reduction Potential)

= E°_{Ni⁺/Ni²⁺} - E°_Fe²⁺/Fe

= +0.049V - (-0.88V)

= 1.37V

Discussion

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