InterviewSolution
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InterviewSolution
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Calculate the electric field intensity E which would be just sufficient to balance the weight of an electron. If this electric field is produced by a second electron located below the first one what would be the distance between them? [Given: e= 1.6 xx 10^(-19)C, m= 9.1 xx 10^(31) kg adn g= 9.8 m//s^(2)] |
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Answer» Solution :As FORCE on a charge in an electric field E `F_(e)= eE` So according to given problem `F_(e) = W` i.e., eE= mg `E= (mg)/(e ) = (9.1 XX 10^(-31) xx 9.8)/(1.6 xx 10^(-19)) = 5.57 xx 10^(-11) (V)/(m)` As this intensity E is produced by another electron B, located at a distance r below A  `E= (1)/(4pi in_(0)) (e )/(r^(2)) "i..e, " r= sqrt((e)/(4pi in_(0)E))` So, `r= [(9 xx 10^(9) xx 1.6 xx 10^(-19))/(5.57 xx 10^(-11))]^(1//2)= 5m` |
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