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Calculate the electric field intensity which would be just sufficient to balance the weight of an electron. If this electric field is produced by a second electron located below the first one what would be the distance between them? [Given: 1.6 xx 10^(-19) C, m = 9.1 xx 10^(-31) kg and g = 9.8 m//s^2]. |
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Answer» Solution :As force on a charge e in an electric field E `F_e = eE` So according to GIVEN PROBLEM, `F_e = W` i.e., `eE = MG` `E = (mg)/(e ) = (9.1 xx 10^(-31) xx 9.8)/(1.6 xx 10^(-19)) = 5.57 xx 10^(11) V/m` As this intensity E is produced by another ELECTRON B, located at a distance r below A.  `E = 1/(4 pi epsilon_0) e/(r^2) "i.e., " r = sqrt((e)/(4 pi epsilon_0 E)` So, `r = [(9 xx 10^(9) xx 1.6 xx 10^(-19))/(5.57 xx 10^(-11))]^(1//2) ~= 5m` . |
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