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Calculate the electronic gas pressure in metallic sodium, at T=0 in which the concentration of free electrons is n=2.5.10^(22)cm^(-3). Use the equation for the pressure of ideal gas. |
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Answer» <P> Solution :From the kinetic theory of gasses we know`P(2)/(3)(U)/(V)` Here `U` is the total interval enrgy of the GAS. This result is applicable to Fermi gas also Now at `T = 0` `U=U_(0)=Nlt E gt = nVlt E gt` so `p=(2)/(3)n lt E gt` `=(2)/(3)nxx(3)/(5)E_(F)=(2)/(5)nE_(F)` `=( ħ^(2))/(5m)(3PI^(2))^(2//3)n^(5//3)` Substituting the value we get `p= 4.92xx10^(4)` atoms |
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