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calculate the emf of the cell Fe(s)+ 2 H+(1M)---- Fe2+(0.001M) +H2(g) (1atm) given E: Fe+2/Fe=-0.44V

Answer» calculate the emf of the cell Fe(s)+ 2 H+(1M)---- Fe2+(0.001M) +H2(g) (1atm) given E: Fe+2/Fe=-0.44V


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