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Calculate the energies of the photons associated with the following radiation: violet light of 413 nm |
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Answer» SOLUTION :ENERGY of photon, `E = h UPSILON ""h = 6.6 xx 10^(-34) Js` `E = (hc)/(lambda)""c = 3 xx 10^(8) ms^(-1)` (i) Violet light, `lambda = 413` nm `E = (6.6 xx 10^(-34) xx 3 xx 10^(8))/(413 xx 10^(-9)) = 0.04794 xx 10^(-17)` `= 4.794 xx 10^(-19) J` `= (4.794 xx 10^(-19))/(1.6 xx 10^(-19)) eV` E = 3 eV (II) X-rays of, `lambda = 0.1` nm `E = (6.6 xx 10^(-34) xx 3 xx 10^(8))/(0.1 xx 10^(-9)) = 198 xx 10^(-17) J` `= (198 xx 10^(-17))/(1.6 xx 10^(-19)) = 123.75 xx 10^(2)` E = 12375 eV (iii) Radio waves, `lambda = 10` m `E = (6.6 xx 10^(-34SD) xx 3 xx 10^(8))/(10) = 1.98 xx 10^(-26)J` `= (1.98 xx 10^(-26))/(1.6 xx 10^(-19)) = 1.2375 xx 10^(-7)` `E = 1.24 xx 10^(-7) eV` |
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