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Calculate the energy in an electric field with permittivity of 56 and field intensity of 36π(in μJ)(a) 3.16(b) 5.16(c) 7.16(d) 9.16I got this question in an international level competition.The doubt is from Electrostatic Energy topic in portion Electrostatic Fields of Electromagnetic Theory

Answer» CORRECT option is (a) 3.16

Easy explanation: The energy in an electric field is given by, W = 0.5 x D x E. SINCE D = εE, we get W = 0.5 x ε x E^2. On SUBSTITUTING the DATA, we get 3.16 microjoule.


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