1.

calculate the energy in kcal/mol of the photons of an electromagnetic radiation of lambda 5700 angastom

Answer»

E=hc/lwhere l.is wavelengthhenceE=6.626*10^-34*3*10^8/5700*10^-10E=19.878*10^-26/5700*10^-10E=0.0034*10^-16E=34*10^-20J



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