1.

Calculate the energy of a photon of wavelength 6600 angstroms.(a) 30 × 10^-19 J(b) 3 × 10^-19 J(c) 300 × 10^-19 J(d) 3000 × 10^-19 JThe question was posed to me in an interview for internship.The above asked question is from Photoelectric Effect in section Dual Nature of Radiation and Matter of Physics – Class 12

Answer»

Right choice is (B) 3 × 10^-19 J

For explanation: GIVEN: λ = 6600 angstrom = 6600 × 10^-10 m.

Energy of a PHOTON = \(\frac {hc}{\lambda }\)

E = \(\frac {(6.6 \TIMES 10^{-34} \times 3 \times 10^8)}{(6600 \times 10^{-10})}\)

E = 3 × 10^-19 J



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