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What is the de – Broglie wavelength associated with an electron, accelerated through a potential difference of 200 volts?(a) 1 nm(b) 0.5 nm(c) 0.0056 nm(d) 0.086 nmI have been asked this question by my college director while I was bunking the class.I'd like to ask this question from Wave Nature of Matter in chapter Dual Nature of Radiation and Matter of Physics – Class 12

Answer» RIGHT choice is (d) 0.086 NM

The explanation is: Given: Potential difference (V) = 200 V

The de – Broglie WAVELENGTH is given as:

λ=\(\frac {H}{p} = \frac {h}{mv} = \frac {1.227}{\sqrt {V}}\) nm

λ=\(\frac {1.227}{\sqrt {200}}\)

λ=0.086 nm


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