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Calculate the energy released by the fission 1 g of .^235U in joule, given that the energy released per fission is 200 MeV. (Avogadro.s number =6.023xx10^23 ) |
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Answer» Solution :The NUMBER of atoms in 1 GM of `.^235U` `="Avogadro.s number"/"Mass number"=(6.023xx10^23)/235=2.563xx10^21` Energy released per fission = 200 MEV `=200xx10^6 xx1.6xx10^(-19)=3.2xx10^(-11)` J . Energy released by 1 G of `.^235U` = Number of atoms x energy released per fission `=2.563xx10^21 xx 3.2xx10^(-11)J = 8.202xx10^10` J |
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