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Calculate the energy required to remove an electron from He_(e)^(+) ion. |
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Answer» Solution :Required ENERGY `E=(nZ^(2)e^(4))/(8 epsi_(0)^(2)n^(2)h^(2))` `E=-(me^(4))/(8 epsi_(0)^(2))*(Z^(2))/(n^(2))` Here `(me^(4))/(8 epsi_(0)^(2)h^(2))=13.6eV` `E=13.6(Z^(2))/(n^(2))eV` for `H_(e)^(+)` ION, Z=2 and n=1 `E=(13.6xx4)/(1)` `=54.4eV` |
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