Saved Bookmarks
| 1. |
Calculate the energyreleased in the nuclear reaction shown below. H_1^2+H_1^2toHe_2^4+"Energy"Mass of H_1^2=2.014102 u mass of He_2^4=4.0026u, 1a.m.u=931 MeV |
| Answer» SOLUTION :ENERGY RELEASED=`Deltamxx931MeV=(2xx2.014102-4.0026)931MeV=23.8336 MEV` | |