InterviewSolution
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InterviewSolution
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Calculate the enthalpy of combustion of ethylene at 300 K at constant pressure, If Its heat of combustion at constant volume (∆U) is – 1406 KJ. |
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Answer» The complete ethylene combustion reaction can be written as, C2H4(g) + 3O2(g) → 2CO2(g) + 2H2O(I) ∆U = -1406 kJ ∆n = np(g) – nr(g) ∆n = 2 – 4 = -2 ∆H = U + RT ∆n(g) ∆H = -1406 + (8.314 x 10-3 x 300 x (-2)) ∆H = – 1410.9 kJ |
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