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Calculate the enthalpy of formation of carbon monoxide (CO) from the following data`:` `(i) C(s) + O(g) rarr CO_(2)(g), Delta_(r)H^(@) = - 393.5 kJ mol^(-1)` (ii) `CO(g) + (1)/(2) O_(2)(g) rarrCO_(2)(g) , Delta _(r) H^(@) = - 283. 0 kJ mol^(-1)` |
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Answer» We aim at` : C(s) +(1)/(2) O_(2)(g) rarr CO(g) , Delta_(f) H^(@) = ?` Subtracting eqn. (ii) fromeqn. (i), we get `C(s) +(1)/(2) O_(2)(g) - CO(g) rarr0, Delta_(r) H^(@) = - 393.5 - (- 283.0) = - 110.5 kJ mol^(-1)` or `C(s) +(1)/(2) O_(2)(g) rarr CO (g) , Delta _(r) H^(@) = - 110.5 kJ` `:. ` Heat of formation of CO is `: Delta _(f) H^(@) = - 110.5 kJ mol^(-1)` |
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