Calculate the entropy change for the following reversible process.H2O(

1.	Calculate the entropy change for the following reversible process.H2O(s) ⇌ H2O(l) ∆fusH is 6 kJ mol-1
Answer» ∆G = ∆H – T∆S When the reaction is carried out at 0°K or ∆S = 0 ∆G = ∆H H₂O_(s) ⇌ H₂O_(I) ∆_fusH = 6 kJ mol^-1 = 6000 Jmol^-1 ∆_fusH = 6 kJ mol^-1 6000 J mol^-1

Calculate the entropy change for the following reversible process.H2O(s) ⇌ H2O(l) ∆fusH is 6 kJ mol-1

Answer»

∆G = ∆H – T∆S

When the reaction is carried out at 0°K

or ∆S = 0

∆G = ∆H

H₂O_(s) ⇌ H₂O_(I)

∆_fusH = 6 kJ mol^-1 = 6000 Jmol^-1

∆_fusH = 6 kJ mol^-1

6000 J mol^-1

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Calculate the entropy change for the following reversible process.H2O(s) ⇌ H2O(l) ∆fusH is 6 kJ mol-1

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