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Calculate the equivalent capacitance between two points A and B in the following figure: |
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Answer» Solution :Here capacitors, `C_(1),C_(2) and C_(3)` are CONNECTED in parallel. i.e., `C.=C_(1)+C_(2)+C_(3)` or `C.=2+3+5` or `C.=10muF` Now. and `C_(4)(10muF)` are in series. `therefore` Equivalent CAPACITANCE of the combination between A and B is `C=(C.xx10)/(C.+10)=(10xx10)/(10+10)=(100)/(20)=5muF`. |
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