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Calculate the external workdone by the system in Kcal, when 40 Kcal of heat is supplied to the system and internal energy rises by 8400J. |
Answer» `dQ=dU+dW` `dU=8400J=(8400)/(4200)K Cal=2 K Cal` `therefore 40 K Cal =2 K Cal+` external work done The external work done `=40-2=38` K Cal |
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