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Calculate the flux density due to a circular conductor of radius 100nm and current 5A in air.(a) 10(b) 100(c) 0.1(d) 1I had been asked this question during an interview for a job.Origin of the question is Magnetization in portion Magnetic Forces and Materials of Electromagnetic Theory

Answer» RIGHT choice is (a) 10

The explanation is: The FIELD intensity of this conductor is I/2πR and since B = μH, the flux density will be B = μI/2πR. PUT I = 5 and R = 100 x 10^-9, thus we get B = 4π x 10^-7x 5/(2π x 100 x 10^-9) = 10 UNITS.


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