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Calculate the focal length of the thin lens shown infigure. The pionts `C_1 and C_2` denote the centres of curvature. |
Answer» As is clear from the ure boththe radii of curvature are positive. Thus, `R_1=+10cm` and `R_2=+20cm.` The focal length is given by `1/f=(mu-1)(1/R_1-1/R_2)` `=(1.5-1)(1/(10cm)-1/(20cm))` `=0.5xx1/(20cm)=1/(40cm)` `or f=40cm.` |
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