Calculate the free enegry change when `1mol` of `NaCI` is dissolved in water at `298K`. Given: a. Lattice enegry of `NaCI =- 778 kJ mol^(-1)` b. Hydration energy of `NaCI - 774.3 kJ mol^(-1)` c. Entropy change at `298 K = 43 J mol^(-1)`

Calculate the free enegry change when `1mol` of `NaCI` is dissolved in

1.	Calculate the free enegry change when `1mol` of `NaCI` is dissolved in water at `298K`. Given: a. Lattice enegry of `NaCI =- 778 kJ mol^(-1)` b. Hydration energy of `NaCI - 774.3 kJ mol^(-1)` c. Entropy change at `298 K = 43 J mol^(-1)`
Answer» Correct Answer - `-9.1555 kj` `= 3.7 kJ mol^(-1) = 3700 J mol^(-1)` `Delta H_("dissolution") = Delta h_(("ionisation")) + Delta H_(("hydration")) = 778 - 774.3` `Delta S_("disolution") = 43 J mol^(-1)` `Delta G_("disolution") = Delta H - T Delta S = 3700 - 298 X 43 = -9114 J, Delta G = - 9.114 kJ`

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Calculate the free enegry change when `1mol` of `NaCI` is dissolved in water at `298K`. Given: a. Lattice enegry of `NaCI =- 778 kJ mol^(-1)` b. Hydration energy of `NaCI - 774.3 kJ mol^(-1)` c. Entropy change at `298 K = 43 J mol^(-1)`

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