Calculate the free energy change in dissolving one mole of sodium chloride at `25^(@)C` . Lattic energy `= + 777.8 kJ mol^(-1)`. Hydration energy of `NaCl = - 774.1 kJ mol^(-1)` and `Delta S ` at `25^(@)C = 0.0 43kJ K^(-1) mol^(-1)`

Calculate the free energy change in dissolving one mole of sodium chlo

1.	Calculate the free energy change in dissolving one mole of sodium chloride at `25^(@)C` . Lattic energy `= + 777.8 kJ mol^(-1)`. Hydration energy of `NaCl = - 774.1 kJ mol^(-1)` and `Delta S ` at `25^(@)C = 0.0 43kJ K^(-1) mol^(-1)`
Answer» Correct Answer - `DeltaG = - 9.1 kJ mol^(_1)` `DeltaH = `Lattice energy `+` Hydration energy `= 777.8-774.1kJ mol^(-1) = 3.7 kJ mol^(-1)` `DeltaG = DeltaH - T DeltaS= 3.7 kJ mol^(-1) -298 K ( 0.043kJ K^(-1) mol^(-1)) = ( 3.7 - 12.8) kJ mol^(-1) = - 9.1 kJ mol^(-1)`

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Calculate the free energy change in dissolving one mole of sodium chloride at `25^(@)C` . Lattic energy `= + 777.8 kJ mol^(-1)`. Hydration energy of `NaCl = - 774.1 kJ mol^(-1)` and `Delta S ` at `25^(@)C = 0.0 43kJ K^(-1) mol^(-1)`

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