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Calculate the free eneryg change at 298 K for the reaction , `Br_(2)(l)+Cl_(2)(g) to BrCl(g)`. For the reaction `DeltaH^(@)=29.3 kJ`& |
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Answer» Correct Answer - `-1721.8 J` `DeltaS= 2 xx 239.7 - [152.3 +223]` `= 104.1 J"mol"^(-1)K^(-1)` `DeltaG = 29300- [298 xx104.1]` `=- 1721. 8J` |
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