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Calculate the free eneryg change at 298 K for the reaction , `Br_(2)(l)+Cl_(2)(g) to BrCl(g)`. For the reaction `DeltaH^(@)=29.3 kJ`&

Answer» Correct Answer - `-1721.8 J`
`DeltaS= 2 xx 239.7 - [152.3 +223]`
`= 104.1 J"mol"^(-1)K^(-1)`
`DeltaG = 29300- [298 xx104.1]`
`=- 1721. 8J`


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