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Calculate the Gibbs energy change for the reaction given below:`Zn_((s))+Cu_((s))^(2+)toCu_((s))+Zn_((aq.))^(2+)` Given that standard Gibbs energy (`G^@`) for `Zn_((aq.))^(2+),Cu_((aq.))^(2+)` are `-147.2 kJ mol^(-1)` and `65.0 kJ mol^(-1)` respectively. |
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Answer» `DeltaG^(@)=SigmaG_("products")^(@)-SigmaG_("reaction")^(@)` `=[0+(-147.2)-(0+65.0)]` `=-212.2 kJ` |
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