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Calculate the half-life period of a radioactive substance, if its activity drops to 16^(th) of its initial value in 30 years. |
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Answer» Solution :`N= (N_(0)) /(16)`, where, `N_(0) = 30` years `N= N_(0) ((1)/(2) )..` `(N)/( N_0) = ((1)/(2))^(4) ""[because "No. of half lives" =4]` `4= ("Time of DISINTEGRATION")/("Half LIFE period")` `RARR (30 " years") /( 4)` = half life period `therefore` Half-life period `=7.5` years |
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