Calculate the heat change accompanying the transformation of C (graphi

1.	Calculate the heat change accompanying the transformation of C (graphite) to C (diamond). Given that the heats of combustion of graphite and diamond are 393.5 and 395.4 kJ mol-1 respectively.
Answer» (i) C (graphite) + O₂ (g) → CO₂ (g) ΔH = -393.5 kJ (ii) C (diamond) + O₂ (g) → CO₂ (g) ΔH = -395.4 kJ C (graphite) → C (diamond), ΔH = ? Subtracting equation (ii) from (i), we get C (graphite) - C (diamond) = 0 ΔH = -393.5 - (-395.4) = +1.9 kJ or, C (graphite) → C (diamond) ΔH = +1.9 kJ

Calculate the heat change accompanying the transformation of C (graphite) to C (diamond). Given that the heats of combustion of graphite and diamond are 393.5 and 395.4 kJ mol-1 respectively.

Answer»

(i) C (graphite) + O₂ (g) → CO₂ (g) ΔH = -393.5 kJ

(ii) C (diamond) + O₂ (g) → CO₂ (g) ΔH = -395.4 kJ

C (graphite) → C (diamond), ΔH = ?

Subtracting equation (ii) from (i), we get

C (graphite) - C (diamond) = 0

ΔH = -393.5 - (-395.4) = +1.9 kJ

or, C (graphite) → C (diamond) ΔH = +1.9 kJ

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Calculate the heat change accompanying the transformation of C (graphite) to C (diamond). Given that the heats of combustion of graphite and diamond are 393.5 and 395.4 kJ mol-1 respectively.

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