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Calculate the heat of formation of acetic acid form the following date: a. `CH_(3)COOH(l) +2O_(2)(g) rarr 2CO_(2)(g) +2H_(2)O(l)DeltaH^(Theta) =- 200.0kcal` b. `C(s) +O_(2) (g) rarr CO_(2)(g), DeltaH^(Theta) =- 94.0 kcal` c. `H_(2)(g) +(1)/(2)O_(2)(g) rarr H_(2)O(l), DeltaH^(Theta) =- 68.0 kcal` |
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Answer» The required equation is `2C(s)+2H_(2)(g)+O_(2)(g)=CH_(3)COOH(l)," "DeltaH=`? this equation can be obtained by multiplying eq. (ii) by 2 and also eq. (iii) by 2 and adding both and finally subtracting eq (i) `[2C+2O_(2)+2H_(2)+O_(2)-CH_(3)COOH(l)-2O_(2)to2CO_(2)+2H_(2)O-2CO_(2)-2H_(2)O]` `DeltaH_(CH_(3)COOH(l))=2xx(-94.96)+2xx(-68.4)-(-207.9)` `=-188.96-138.8+207.9` `=-325.76+207.9=-117.86kcal` |
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