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Calculate the heat of neutralization by mixing `200mL` of `0.1 MH_(2)SO_(4)` and `200mL ` of `0.2 MKOH `if heat generated by the mixing is `2.3 kJ`. |
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Answer» `Meq. `of `H_(2)SO_(4)=200xx0.1xx2=40` `(H_(2)SO_(4)` is dibasic `)` `Meq. `of `KOH=200xx0.2=40` `:. 40 Meq. Of H_(2)SO_(4)` and `40Meq.` of `KOH` on mixing gives heat `=2.3kJ` `:. 1000meq. ` of `H_(20SO_(4)` and `1000Meq.` of `KOH` on mixing gives heat `=(2.3xx1000)/(40)=57.5kJ` |
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