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Calculate the impact parameter of 5.0 MeV alpha-particle scattered by 10^(@) when it approaches a gold nuclcus (Z = 79). |
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Answer» Solution :`Z_(1) = 2 , Z_(2) , = Z = 79` Impact parameter, ` B = (Ze^(2) cot (THETA//2))/(4 pi epsilon_(0) ((1)/(2) mv^(2)))` Here` theta = 10^(@) , E = (1)/(2) mv^(2) = 5.0 xx 1.6 xx 10^(-13) `J `(1)/(4 pi epsilon_(0)) = 9 xx 10^(-9) Nm^(2) C^(-2)` `therefore b = (79 xx (1.6 xx 10^(-19))^(2) cot 5^(@) xx 9 xx 10^(@))/(5.0 xx 1.6 xx 10^(-13)) = 2.6 xx 10^(-13)` m |
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