1.

Calculate the impact parameter of a 5 MeV particle scattered by `90^(@)`, when it approach a gold nucleus (Z=79).

Answer» Correct Answer - `2.27xx10^(-14)m`
Here, `b=? KE=5MeV=5xx1.6xx10^(-13)J`
`theta=90^(@), Z=79`
`b=(Ze^(2)cot theta//2)/(4pi in_(0)(KE))`
`=(9xx10^(9)xx79(1.6xx10^(-19))^(2)cot 45^(@))/(5xx1.6xx10^(-13))`
`b=2.27xx10^(-14)m`


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