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Calculate the impact parameter of a 5 MeV particle scattered by `90^(@)`, when it approach a gold nucleus (Z=79). |
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Answer» Correct Answer - `2.27xx10^(-14)m` Here, `b=? KE=5MeV=5xx1.6xx10^(-13)J` `theta=90^(@), Z=79` `b=(Ze^(2)cot theta//2)/(4pi in_(0)(KE))` `=(9xx10^(9)xx79(1.6xx10^(-19))^(2)cot 45^(@))/(5xx1.6xx10^(-13))` `b=2.27xx10^(-14)m` |
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