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Calculate the impact parameter of a 5MeV alpha particle scatterd by `10^@` when it approaches a gold nucleus. Take Z=79 for gold. |
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Answer» Here, `K.E. =1/2 mv^(2)=5MeV` `5xx1.6xx10^(-13)J` , `theta=10^@, Z=79,b=?` As `b=(Ze^(2) cot theta//2)/(4pi in_0(1/2 mv^(2)))` `:. b=(9xx10^(9)xx79(1.6 xx10^(-19))^(2) cot 5^@)/(5xx1.6xx10^(-13))` `(tan 5^@ =0.0875)` `=(9xx79xx1.6xx1.6xx10^(-16))/(8xx0.0875)=2.6 xx 10^(-13) m` |
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