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Calculate the increase in the internal energy of `10 g` of water when it is heated from `0^(0)C to 100^(0)C` and converted into steam at `100 kPa`. The density of steam `=0.6 kg m^(-3)`, specific heat capacity of water `=4200 J kg^(-1 ^(0)C^(-3)` ,latent heat of vaporization of water `=2.25xx10 6 J kg^(-1)` |
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Answer» Correct Answer - A::B::D `V_i=m/rho_i=0.01/1000=10^-5m^3` `V_f=m/rho_f=0.01/0.6=0.0167m^3` `DeltaU=Q-W` `=msDeltatheta+mL-p_0DeltaV` `=(0.01xx4200xx100)+(0.01)(2.5xx10)^6-10^5(0.0167-10^-5)` `=27530J` |
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