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Calculate the increase in the internal energy of 10 g of water when it is heated from `0^(0)C to 100^(0)C` and converted into steam at 100 kPa. The density of steam `=0.6 kg m^(-3)` specific heat capacity of water `=4200 J kg^(-1 ^(0)C^(-3)` latent heat of vaporization of water `=2.25xx10 6 J kg^(-1)` |
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Answer» Correct Answer - A::B::D Mass` = 10kg = 0.01kg` `P = 10^5kpa` `Delta Q = QH_2 O 0^@-100^@+QH_(2) O-steam` `0.01xx4200xx100+0.01xx2.5xx10^3` ` = 4200+2500 = 29200` `Delta W = paV` `Delta V = ((0.01)/(06))-((0.01)/(1000)) = 0.01699` `DeltaW = pDeltaV = 0.01699xx10^5 = 1699J` ` = 27501 = 2.75xx10^4J |
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